AP EAMCET · Maths · Quadratic Equation
The solution of the equation \(2 x^3-x^2-22 x-24=0\), when two of the roots are in the ratio \(3: 4\) is
- A \(3,4, \frac{1}{2}\)
- B \(\frac{-3}{2},-2,4\)
- C \(\frac{-1}{2}, \frac{3}{2}, 2\)
- D \(\frac{-3}{2}, 2, \frac{5}{2}\)
Answer & Solution
Correct Answer
(B) \(\frac{-3}{2},-2,4\)
Step-by-step Solution
Detailed explanation
Given equation, \[ 2 x^3-x^2-22 x-24=0 \] Put \(x=-2\) \[ \begin{aligned} & 2(-2)^3-(-2)^2-22(-2)-24 \\ \Rightarrow \quad & -16-4+44-24=0 \end{aligned} \] \(\therefore x+2\) is root of equation \(2 x^3-x^2-22 x-24=0\)…
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