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AP EAMCET · Maths · Circle

Find the equation of the circle passing through (1,-2) and touching the x-axis at (3,0).

  1. A x2+y2+6x4y9=0
  2. B x2+y26x4y+9=0
  3. C x2+y26x4y9=0
  4. D x2+y26x+4y+9=0
Verified Solution

Answer & Solution

Correct Answer

(D) x2+y26x+4y+9=0

Step-by-step Solution

Detailed explanation

Let required circle equation is x-h2+y-k2=r2 Given that circle touching the x axis at 3, 0. So x axis is a tangent to the given circle i.e perpendicular distance from centre to tangent must be equal to radius. ⇒k=r x-h2+y-k2=k2 It is passing through…