AP EAMCET · Maths · Probability
Let \(A\) and \(B\) be two independent events such that \(P(B)>P(A)\). If the probability that both A and B happen is \(\frac{1}{12}\) and the probability that neither Anor B happens is \(\frac{1}{2}\) then
- A \(P(A)=\frac{1}{6}, P(B)=\frac{1}{2}\)
- B \(\mathrm{P}(\mathrm{A})=\frac{1}{4}, \mathrm{P}(\mathrm{B})=\frac{1}{3}\)
- C \(\mathrm{P}(\mathrm{A})=\frac{1}{6}, \mathrm{P}(\mathrm{B})=\frac{1}{5}\)
- D \(\mathrm{P}(\mathrm{A})=\frac{1}{6}, \mathrm{P}(\mathrm{B})=\frac{1}{3}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{P}(\mathrm{A})=\frac{1}{4}, \mathrm{P}(\mathrm{B})=\frac{1}{3}\)
Step-by-step Solution
Detailed explanation
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