ExamBro
ExamBro
AP EAMCET · PHYSICS · Gravitation

A projectile is thrown straight upward from the earth's surface with an initial speed v=αvE, where α is a constant and vE is the escape speed. The projectile travels upto a height 800 km from earth's surface, before it comes to rest. The value of the constant α is,
(Radius of the earth =6400 km)

  1. A 13
  2. B 12
  3. C 23
  4. D 34
Verified Solution

Answer & Solution

Correct Answer

(A) 13

Step-by-step Solution

Detailed explanation

Escape velocity is given by: vE=2GMR At Earth's surface: Kinetic energy of the particle KE1=12mv2=12mα2vE2=12mα2×2GMR=GMmα2R Potential energy of the particle: PE1=-GMmR At certain height the particle stops for a moment: KE2=0 PE2=-GMmR+h Applying conservation…
Same subject
Explore more questions on app