AP EAMCET · PHYSICS · Work Power Energy
A person holds a ball of mass 0.25 kg in his hand and throws it, so that it leaves his hand with a speed of \(12 \mathrm{~m} \mathrm{~s}^{-1}\). In this process, if his hand moved through a distance of 0.9 m, then the net force acted on the ball is
- A 40 N
- B 20 N
- C 25 N
- D 10 N
Answer & Solution
Correct Answer
(B) 20 N
Step-by-step Solution
Detailed explanation
\(F = m \frac{v^2}{2s}\) \(F = 0.25 \mathrm{~kg} \times \frac{(12 \mathrm{~m/s})^2}{2 \times 0.9 \mathrm{~m}}\) \(F = 20 \mathrm{~N}\)
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