AP EAMCET · PHYSICS · Oscillations
A particle undergoing simple harmonic motion has an amplitude of \(10 \mathrm{~cm}\). When the particle is at a displacement of \(6 \mathrm{~cm}\) from the centre, then the ratio of its kinetic energy to potential energy is
- A \(3: 2\)
- B \(9: 4\)
- C \(16: 9\)
- D \(4: 3\)
Answer & Solution
Correct Answer
(C) \(16: 9\)
Step-by-step Solution
Detailed explanation
Amplitude of particle performing SHM, \[ A=10 \mathrm{~m} \] Instantaneous displacement of the particle, \[ x=6 \mathrm{~cm} \] Kinetic energy of the particle, \[ K=\frac{1}{2} m \omega^2\left(A^2-x^2\right) \] Potential energy of particle,…
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