AP EAMCET · PHYSICS · Magnetic Effects of Current
A particle of mass \(1 \times 10^{-26} \mathrm{~kg}\) and charge \(1.6 \times 10^{-19} \mathrm{C}\) travelling with a velocity \(1.28 \times 10^6 \mathrm{~ms}^{-1}\) along the positive \(X\)-axis enters a region in which a uniform electric field \(\mathbf{E}\) and a uniform magnetic field of induction \(\mathbf{B}\) are present. If \(\mathbf{E}=-102.4 \times 10^3 \hat{\mathbf{k}} \mathrm{NC}^{-1}\) and \(\mathbf{B}=8 \times 10^{-2} \hat{\mathbf{j}} \mathrm{Wbm}^{-2}\) the direction of motion of the particles is
- A along the positive \(X\)-axis
- B along the negative \(X\)-axis
- C at \(45^{\circ}\) to the positive \(X\)-axis
- D at \(135^{\circ}\) to the positive \(X\)-axis
Answer & Solution
Correct Answer
(A) along the positive \(X\)-axis
Step-by-step Solution
Detailed explanation
\(\begin{aligned} m & =1 \times 10^{-26} \mathrm{~kg}, q=1.6 \times 10^{-19} \mathrm{C} \\ v & =1.28 \times 10^6 \mathrm{~m} / \mathrm{s} \end{aligned}\) Electric field, \(\mathbf{E}=-102.4 \times 10^3 \hat{\mathbf{k}} \mathrm{N} / \mathrm{C}\) Magnetic field,…
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