AP EAMCET · PHYSICS · Work Power Energy
A particle is released from a height \(H\). At a certain height, its kinetic energy is half of its potential energy with reference to the surface of the earth. Height and speed of the particle at that instant are respectively
- A \(\frac{H}{3}, \sqrt{\frac{2 g H}{3}}\)
- B \(\frac{H}{3}, 2 \sqrt{\frac{g H}{3}}\)
- C \(\frac{2 H}{3}, \sqrt{2 g H}\)
- D \(\frac{2 H}{3}, \sqrt{\frac{2 g H}{3}}\)
Answer & Solution
Correct Answer
(D) \(\frac{2 H}{3}, \sqrt{\frac{2 g H}{3}}\)
Step-by-step Solution
Detailed explanation
Total mechanical energy of particle, i.e. \(PE + KE =m g H\) ...(i) Given, \( \mathrm{KE}=\frac{1}{2} \mathrm{PE} \) i.e. \( \begin{aligned} & \frac{\mathrm{KE}}{\mathrm{PE}}=\frac{1}{2} \\ & \mathrm{PE}=2 \mathrm{KE} \end{aligned} \) or Substituting in this Eq. (i), we get…
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