AP EAMCET · PHYSICS · Oscillations
A particle is executing simple harmonic motion. If the minimum time taken by the particle to move from extreme position to half of the amplitude is \(t_1\), and the minimum time taken by the particle to move from mean position to half of the amplitude is \(t_2\), then
- A \(t_1=t_2\)
- B \(t_1=0.5 t_2\)
- C \(t_1=2 t_2\)
- D \(t_1=\sqrt{2} t_2\)
Answer & Solution
Correct Answer
(C) \(t_1=2 t_2\)
Step-by-step Solution
Detailed explanation
For the particle to move from extreme position to half of the amplitude \(\begin{aligned} & \mathrm{x}=\mathrm{A} \cos \omega \mathrm{t}_1 \\ & \frac{\mathrm{A}}{2}=\mathrm{A} \cos \omega \mathrm{t}_1 \\ & \mathrm{t}_1=\frac{\pi}{3 \omega} \end{aligned}\) For the particle to…
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