AP EAMCET · PHYSICS · Oscillations
A particle initially at the mean position is executing simple harmonic motion with an angular frequency \(\frac{\pi}{4} \mathrm{rad} \mathrm{s}^{-1}\). The ratio of the distances travelled by the particle in the first second and second is
- A \(2: 1\)
- B \(1: 1\)
- C \((1+\sqrt{3}): 1\)
- D \((1+\sqrt{2}): 1\)
Answer & Solution
Correct Answer
(D) \((1+\sqrt{2}): 1\)
Step-by-step Solution
Detailed explanation
Angular frequency, \(\omega=\frac{\pi}{4}\) Displacement of particle executing SHM at \(t=1 \mathrm{~s}\) \(Y_1=A \sin \frac{\pi}{4}=\frac{A}{\sqrt{2}}\) Displacement of particles executing S H M at \(t=2 s\) \(Y_2=A \sin \frac{2 \pi}{4}=A\) Distance covered in time…
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