AP EAMCET · PHYSICS · Nuclear Physics
A nucleus has mass number \(A_1\) and volume \(V_1\). Another nucleus has mass number \(A_2\) and volume \(V_2\). If the relation the mass numbers is \(\mathrm{A}_2=3 \mathrm{~A}_1\), then \(\frac{\mathrm{V}_1}{\mathrm{~V}_2}=\)
- A \(3^{\frac{1}{3}}\)
- B \(\left(\frac{1}{3}\right)^{\frac{1}{3}}\)
- C \(\frac{1}{3}\)
- D \(\frac{1}{\sqrt{3}}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{3}\)
Step-by-step Solution
Detailed explanation
We have \(\begin{aligned} & \mathrm{V} \propto \mathrm{A} \\ & \frac{\mathrm{V}_1}{\mathrm{~V}_2}=\frac{\mathrm{A}_1}{\mathrm{~A}_2}=\frac{1}{3}\end{aligned}\)
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