AP EAMCET · PHYSICS · Work Power Energy
A motor engine pumps \(1800 \mathrm{~L}\) of water per minute from a well of depth \(30 \mathrm{~m}\) and allows to pass through a pipe of cross-sectional area \(30 \mathrm{~cm}^2\). Then the power of the engine is (Acceleration due to gravity, \(g=10 \mathrm{~ms}^{-2}\) )
- A \(20.5 \mathrm{~kW}\)
- B \(15.5 \mathrm{~kW}\)
- C \(10.5 \mathrm{~kW}\)
- D \(9.5 \mathrm{~kW}\)
Answer & Solution
Correct Answer
(C) \(10.5 \mathrm{~kW}\)
Step-by-step Solution
Detailed explanation
Given, depth of a well, \(d=30 \mathrm{~m}\) water quantity per minute \(=1800\) litre cross-section area of pipe, \(A=30 \mathrm{~cm}^2\) \(=30 \times 10^{-4} \mathrm{~m}^2\) Now, velocity of water a jet…
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