AP EAMCET · Chemistry · Thermodynamics (C)
The standard Gibb's energy \(\left(\Delta G^{\circ}\right)\) for the following reaction is
\(\begin{aligned} & A(s)+B^{2+}(a q) \rightleftharpoons A^{2+}(a q)+B(s), \\ & K_C=10^{12} \text { at } 25^{\circ} \mathrm{C}\left(K_C=\text { equilibrium constant }\right)\end{aligned}\)
- A \(-150 \mathrm{~kJ}\)
- B \(-96.80 \mathrm{~kJ}\)
- C \(-68.47 \mathrm{~kJ}\)
- D \(-100 \mathrm{~kJ}\)
Answer & Solution
Correct Answer
(C) \(-68.47 \mathrm{~kJ}\)
Step-by-step Solution
Detailed explanation
The standard Gibb's free energy change \(\left(\Delta G^{\circ}\right)\) at standard conditions is given by the formula \(\Delta G^{\circ}=-R T \ln K_{\text {eq }}\) where, \(R\) is gas constant \(=8.314 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\),…
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