AP EAMCET · PHYSICS · Gravitation
A mass of \(6 \times 10^{24} \mathrm{~kg}\) is to be compressed in the form of a solid sphere such that the escape velocity from its surface is \(3 \times 10^4 \mathrm{~ms}^{-1}\). The radius of the sphere is (Universal gravitational constant \(=6.66 \times 10^{-11} \mathrm{~N} \mathrm{~m}^2 \mathrm{~kg}^{-2}\) )
- A 483 km
- B 575 km
- C 789 km
- D 888 km
Answer & Solution
Correct Answer
(D) 888 km
Step-by-step Solution
Detailed explanation
\(R = \frac{2GM}{v_e^2}\) \(R = \frac{2 \times 6.66 \times 10^{-11} \mathrm{~N} \mathrm{~m}^2 \mathrm{~kg}^{-2} \times 6 \times 10^{24} \mathrm{~kg}}{(3 \times 10^4 \mathrm{~ms}^{-1})^2}\) \(R = 8.88 \times 10^5 \mathrm{~m}\) \(R = 888 \mathrm{~km}\)
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