AP EAMCET · PHYSICS · Motion In Two Dimensions
A body is projected at an angle of \(45^{\circ}\) with the horizontal with a velocity of \(60 \sqrt{2} \mathrm{~ms}^{-1}\). Then the angle made by its velocity with the horizontal after \(6 \mathrm{~s}\) is
- A \(45^{\circ}\)
- B \(0^{\circ}\)
- C \(30^{\circ}\)
- D \(60^{\circ}\)
Answer & Solution
Correct Answer
(B) \(0^{\circ}\)
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Detailed explanation
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