AP EAMCET · PHYSICS · Oscillations

A mass $M$ attached to a horizontal spring executes simple harmonic motion with amplitude $A_1$. When mass $M$ passes mean position then a smaller mass $m$ is attached to it and both of them together executing simple harmonic motion with amplitude $A_2$. Then the value of $\frac{A_1}{A_2}$ is

A $\sqrt{\frac{m^2+M^2}{M^2}}$
B $\sqrt{\frac{m+M}{M^2}}$
C $\sqrt{\frac{m+M}{M}}$
D $\frac{m+M}{M}$

Verified Solution

Answer & Solution

Correct Answer

(C) $\sqrt{\frac{m+M}{M}}$

Step-by-step Solution

Detailed explanation

For SHM , at mean position, $\mathrm{F}_{\text {net }}=0$ $\therefore$ By conservation of momentum,…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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From AP EAMCET

When a body is in

S H M

, then match the following.

$List - I$		$List - II$
$(A)$	Velocity is maximum	$(I)$	Acceleration is maximum
$(B)$	$KE$ is ${(\frac{3}{4})}^{th}$ of total energy	$(II)$	At mean position
$(C)$	$PE$ is ${(\frac{3}{4})}^{th}$ of total energy	$(III)$	At half of the amplitude
$(D)$	Acceleration is maximum	$(IV)$	At $\frac{\sqrt{3}}{2}$ times the amplitude

AP EAMCET 2019 Easy

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