AP EAMCET · PHYSICS · Thermodynamics
Temperature of a cold reservoir of a Carnot engine is \(127^{\circ} \mathrm{C}\). If the efficiency of the Carnot engine is \(20 \%\), then the temperature of the hot reservoir is
- A \(500^{\circ} \mathrm{C}\)
- B \(227^{\circ} \mathrm{C}\)
- C \(273^{\circ} \mathrm{C}\)
- D \(400^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(B) \(227^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
As \(\eta=1-\frac{\mathrm{T}_{\mathrm{C}}}{\mathrm{T}_{\mathrm{H}}} \Rightarrow 0.2=1-\frac{400}{\mathrm{~T}_{\mathrm{H}}}\)…
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