When a body is in SHM, then match the following. List - I List - II A Velocity is maximum I Acceleration is maximum B KE is 34th of total energy II At mean position C PE is 34th of total energy III At half of the amplitude D Acceleration is maximum IV At 32 times the amplitude

AP EAMCET · PHYSICS · Oscillations

When a body is in $S H M$ , then match the following.

$List - I$ $List - II$

$(A)$ Velocity is maximum $(I)$ Acceleration is maximum

$(B)$ $KE$ is ${(\frac{3}{4})}^{th}$ of total energy $(II)$ At mean position

$(C)$ $PE$ is ${(\frac{3}{4})}^{th}$ of total energy $(III)$ At half of the amplitude

$(D)$ Acceleration is maximum $(IV)$ At $\frac{\sqrt{3}}{2}$ times the amplitude

A

$A$ $B$ $C$ $D$

$III$ $I$ $IV$ $II$
B

$A$ $B$ $C$ $D$

$I$ $III$ $IV$ $II$
C

$A$ $B$ $C$ $D$

$II$ $III$ $IV$ $I$
D

$A$ $B$ $C$ $D$

$II$ $I$ $IV$ $III$

Verified Solution

Answer & Solution

Correct Answer

(C)

$A$	$B$	$C$	$D$
$II$	$III$	$IV$	$I$

Step-by-step Solution

Detailed explanation

In S.H.M. If equation of S.H.M. is given byy=Asinωt Velocity v=ωA2-x2 And Acceleration a=-ω2x Here ω is angular frequency and x is displacement from mean position. From velocity equation we can see that velocity will be max when x=0 i.e. particle is at mean…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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$List - I$		$List - II$
$(A)$	Velocity is maximum	$(I)$	Acceleration is maximum
$(B)$	$KE$ is ${(\frac{3}{4})}^{th}$ of total energy	$(II)$	At mean position
$(C)$	$PE$ is ${(\frac{3}{4})}^{th}$ of total energy	$(III)$	At half of the amplitude
$(D)$	Acceleration is maximum	$(IV)$	At $\frac{\sqrt{3}}{2}$ times the amplitude