AP EAMCET · PHYSICS · Work Power Energy
A man who is running has half the kinetic energy of a boy of half his mass. The man speeds up by \(1 \mathrm{~ms}^{-1}\) and then has the same kinetic energy as the boy. The initial speed of the boy is
- A \(\sqrt{2}+1 \mathrm{~ms}^{-1}\)
- B \(2(\sqrt{2}+1) \mathrm{ms}^{-1}\)
- C \(\sqrt{2} \mathrm{~ms}^{-1}\)
- D \(2 \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(B) \(2(\sqrt{2}+1) \mathrm{ms}^{-1}\)
Step-by-step Solution
Detailed explanation
According to the question, let the mass of man be \(m\). So, mass of boy is \(\frac{m}{2}\). Let speed of man be \(v_1\) and that of boy be \(v_2\). \(\therefore\) Kinetic energy of man \(=\frac{1}{2}\) kinetic energy of boy or…
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