AP EAMCET · PHYSICS · Electromagnetic Induction
A horizontal telegraph wire of length 30 m spread east to west fell down freely from a height of 20 m. If the resistance of the wire is \(40 \Omega\) and the horizontal component of the earth's magnetic field at the place is \(2 \times 10^{-5} \mathrm{~T}\), then the induced current when the wire reaches the ground is (Acceleration due to gravity \(=10 \mathrm{~m} \mathrm{~s}^{-2}\) )
- A 0.3 mA
- B 3 mA
- C 3 A
- D 0.03 A
Answer & Solution
Correct Answer
(A) 0.3 mA
Step-by-step Solution
Detailed explanation
\(v = \sqrt{2gh}\) \(v = \sqrt{2 \times 10 \, \mathrm{m} \mathrm{s}^{-2} \times 20 \, \mathrm{m}} = 20 \, \mathrm{m} \mathrm{s}^{-1}\) \(\epsilon = BLv\)…
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