AP EAMCET · PHYSICS · Magnetic Effects of Current
In a wire of radius 1 mm, a steady current of 2 A uniformly distributed across the cross-section of the wire is flowing. Then the magnetic field at a point 0.25 mm from the centre of the wire is
- A \(100 \mu \mathrm{~T}\)
- B \(200 \mu \mathrm{~T}\)
- C \(300 \mu \mathrm{~T}\)
- D \(400 \mu \mathrm{~T}\)
Answer & Solution
Correct Answer
(A) \(100 \mu \mathrm{~T}\)
Step-by-step Solution
Detailed explanation
\( B = \frac{\mu_0 I r}{2 \pi R^2} \) \( B = \frac{(4 \pi \times 10^{-7}) (2 \text{ A}) (0.25 \times 10^{-3} \text{ m})}{2 \pi (1 \times 10^{-3} \text{ m})^2} \) \( B = 1 \times 10^{-4} \text{ T} \) \( B = 100 \mu \text{T} \)
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