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AP EAMCET · PHYSICS · Dual Nature of Matter

In a photoelectric experiment light of wavelength 800 nm produces photoelectrons with the smallest de Broglie wavelength of 1 nm. Then the work function of the metal used in the experiment is nearly

  1. A 0.05 eV
  2. B 0.53eV
  3. C 2.03eV
  4. D 4.02eV
Verified Solution

Answer & Solution

Correct Answer

(A) 0.05 eV

Step-by-step Solution

Detailed explanation

Kinetic energy of the electron having de Broglie wavelength λ can be written as, λb=hp=h2mK⇒K=h22mλb2 For the given values, we can write: hcλ=K+ϕ⇒hc800×10-9=h22m×1×10-92+ϕ⇒ϕ=hc800×10-9-h22m×1×10-92…
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