AP EAMCET · PHYSICS · Center of Mass Momentum and Collision
A cricket ball hits the ground with a speed of \(5 \mathrm{~m} \mathrm{~s}^{-1}\) making an angle \(30^{\circ}\) with the horizontal. If the coefficient of restitution is 0.2 , the speed of the reflected ball in \(\mathrm{m} \mathrm{s}^{-1}\) is
- A \(\sqrt{22}\)
- B \(\sqrt{15}\)
- C \(\sqrt{19}\)
- D \(\sqrt{11}\)
Answer & Solution
Correct Answer
(C) \(\sqrt{19}\)
Step-by-step Solution
Detailed explanation
We know that, coefficient of restitution, \(e=\left(\frac{\text { Relative velocity of separation }}{\text { Relative velocity of approach }}\right)\) Now, given collision is as shown As impact is along normal to surface it does not change the horizontal component of ball. Now…
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