AP EAMCET · PHYSICS · Laws of Motion
A block of mass 5 kg is placed on a rough horizontal surface having coefficient of friction 0.5 . If a horizontal force of 60 N is acting on it, then the acceleration of the block is (Acceleration due to gravity, \(g=10 \mathrm{~ms}^{-2}\) ).
- A \(7 \mathrm{~ms}^{-2}\)
- B \(5 \mathrm{~ms}^{-2}\)
- C \(10 \mathrm{~ms}^{-2}\)
- D \(15 \mathrm{~ms}^{-2}\)
Answer & Solution
Correct Answer
(A) \(7 \mathrm{~ms}^{-2}\)
Step-by-step Solution
Detailed explanation
Acceleration of the block is \(\begin{aligned} & \mathrm{a}=\frac{60-25}{5}=\frac{35}{5} \\ & =7 \mathrm{~m} / \mathrm{s}^2 \\ & \mathrm{f}=5 \times 10 \times 0.5 \\ & =25 \mathrm{~N}\end{aligned}\)
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