AP EAMCET · Maths · Ellipse
The product of the lengths of the perpendiculars drawn from the foci of the ellipse \(\frac{x^2}{9}+\frac{y^2}{25}=1\) to the tangent at any point on the ellipse is
- A 6
- B 7
- C 8
- D 9
Answer & Solution
Correct Answer
(D) 9
Step-by-step Solution
Detailed explanation
Given ellipse equation: \(\frac{x^2}{9}+\frac{y^2}{25}=1\) Compare with standard form \(\frac{x^2}{b^2}+\frac{y^2}{a^2}=1\): \(b^2=9\) The product of the lengths of the perpendiculars from the foci to any tangent of an ellipse is equal to the square of its semi-minor axis.…
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