AP EAMCET · PHYSICS · Wave Optics
In Young's double slit experiment, the two slits are illuminated by a light beam consisting of wavelengths \(4200 Å\) and \(5040 Å\). If the distance between the slits is \(2.4 \mathrm{~mm}\) and the distance between the slits and the screen is \(200 \mathrm{~cm}\), the minimum distance from the central bright fringe to the point where the bright fringes due to both the wavelengths coincide is
- A 0.7 mm
- B 1.4 mm
- C 2.1 mm
- D 2.8 mm
Answer & Solution
Correct Answer
(C) 2.1 mm
Step-by-step Solution
Detailed explanation
Let \(n_1\) fringes of \(\lambda_1=4200 Å\) and \(n_2\) fringes of \(\lambda_2=5040 Å\) wavelength are formed in a fixed distance on screen. So, \(n \lambda=\) constant or \(n_1 \lambda_1=n_2 \lambda_2\) For minimum distance to be coincide,…
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