AP EAMCET · Chemistry · Thermodynamics (C)
If the standard enthalpy of sublimation \(\left(\Delta_{\mathrm{gos}} \mathrm{H}^{\circ}\right)\) of solid \(\mathrm{CO}_2\), naphthalene, \(\mathrm{Li}\) and \(\mathrm{Na}\) are \(25.2,73.0,162,108\) \(\mathrm{kJ}\) mol respectively, the order of sublimation of these substances with temperature is
- A \(\mathrm{Na}>\mathrm{Li}>\) Naphthalene \(>\) Solid \(\mathrm{CO}_2\)
- B Solid \(\mathrm{CO}_2>\mathrm{Na}>\) Naphthalene \(>\mathrm{Li}\)
- C Solid \(\mathrm{CO}_2>\) Naphthalene \(>\mathrm{Na}>\mathrm{Li}\)
- D \(\mathrm{Li}>\mathrm{Na}>\) Naphthalene \(>\) Solid \(\mathrm{CO}_2\)
Answer & Solution
Correct Answer
(C) Solid \(\mathrm{CO}_2>\) Naphthalene \(>\mathrm{Na}>\mathrm{Li}\)
Step-by-step Solution
Detailed explanation
The lower the sublimation enthalpy, the lower is the heat required to sublime it and easier for that substance to get sublimed. Thus, the order of ease of sublimation will be:solid \(\mathrm{CO}_2>\mathrm{Na}>\mathrm{Na}>\mathrm{Li}\)
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