AP EAMCET · PHYSICS · Electrostatics
Three point charges \(+q,+2 q\) and \(+4 q\) are placed along a straight line such that the charge \(+2 q\) lies at equidistant from the other two charges. The ratio of the net electrostatic force on charges \(+q\) and \(+4 q\) is
- A \(1: 1\)
- B \(1: 2\)
- C \(1: 4\)
- D \(1: 3\)
Answer & Solution
Correct Answer
(D) \(1: 3\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & F_1=\frac{k(q)(2 q)}{r^2}+\frac{k(q)(4 q)}{4 r^2}=\frac{12 \mathrm{kq}^2}{4 r^2} \\ & F_2=\frac{k(4 q)(2 q)}{r^2}+\frac{k(4 q)(q)}{4 r^2}=\frac{36 \mathrm{kq}^2}{4 r^2} \\ & \therefore \frac{F_1}{F_2}=\frac{12}{36}=1: 3\end{aligned}\)
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