AP EAMCET · Maths · Straight Lines
If \(p\) and \(q\) are lengths of the perpendiculars from origin to the lines \(x \sec (\theta)+y \operatorname{cosec}(\theta)=k\) and \(x \cos (\theta)-y \sin (\theta)=k \cos (2 \theta)\) respectively, then
- A \(p^2+4 q^2=k^2\)
- B \(4 p^2+q^2=k^2\)
- C \(p^2+q^2=4 k^2\)
- D \(p^2+q^2=k^2\)
Answer & Solution
Correct Answer
(B) \(4 p^2+q^2=k^2\)
Step-by-step Solution
Detailed explanation
\(p=\frac{|0+0-k|}{\sqrt{\sec ^2 \theta+\operatorname{cosec}^2 \theta}}, q=\frac{\left|0-0-k \cos ^2 \theta\right|}{\sqrt{\cos ^2 \theta+\sin ^2 \theta}}\) \(\Rightarrow \quad p^2=\frac{k^2}{\sec ^2 \theta+\operatorname{cosec}^2 \theta}, q^2=k^2 \cos ^2 2 \theta\)…
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