AP EAMCET · Maths · Circle
If the circle \(S \equiv x^2+y^2+2 g x+4 y+1=0\) bisects the circumference of the circle \(\mathrm{x}^2+\mathrm{y}^2-2 \mathrm{x}-3=0\), then the radius of circle \(\mathrm{S}=0\) is
- A 5
- B \(\sqrt{12}\)
- C 25
- D 12
Answer & Solution
Correct Answer
(B) \(\sqrt{12}\)
Step-by-step Solution
Detailed explanation
\((2g+2)x + 4y + 4 = 0\) is the common chord. Center of \(x^2+y^2-2x-3=0\) is \((1,0)\). Substitute center into common chord: \((g+1)(1) + 2(0) + 2 = 0 \Rightarrow g = -3\). Circle S is \(x^2+y^2-6x+4y+1=0\). Radius of S:…
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