AP EAMCET · PHYSICS · Mechanical Properties of Fluids
A body of volume \(\mathrm{V}\) floats on water with \(\frac{1}{3}\) of its volume above the surface. The volume of the object above the surface when floating on a liquid of specific gravity 1.5 is
- A \(\frac{3 \mathrm{~V}}{8}\)
- B \(\frac{4 \mathrm{~V}}{9}\)
- C \(\frac{5 \mathrm{~V}}{9}\)
- D \(\frac{2 \mathrm{~V}}{3}\)
Answer & Solution
Correct Answer
(C) \(\frac{5 \mathrm{~V}}{9}\)
Step-by-step Solution
Detailed explanation
We have \(\frac{\mathrm{V}^{\prime}}{\mathrm{V}}=\frac{\rho}{\rho \hat{l}}\), \(\mathrm{V}^{\prime}=\) Volume of substance inside the liquid \(\begin{aligned} & \text { So, } \frac{2}{3}=\frac{\rho}{1000} \\ & \rho=\frac{2000}{3} \mathrm{~kg} / \mathrm{m}^3\end{aligned}\) When,…
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