AP EAMCET · PHYSICS · Center of Mass Momentum and Collision
A body of mass 2 kg is moving towards north with a velocity of \(20 \mathrm{~m} \mathrm{~s}^{-1}\) and another body of mass 3 kg is moving towards east with a velocity of \(10 \mathrm{~m} \mathrm{~s}^{-1}\). The magnitude of the velocity of the centre of mass of the system of the two bodies is
- A \(20 \mathrm{~m} \mathrm{~s}^{-1}\)
- B \(10 \mathrm{~m} \mathrm{~s}^{-1}\)
- C \(15 \mathrm{~m} \mathrm{~s}^{-1}\)
- D \(2 \sqrt{5} \mathrm{~m} \mathrm{~s}^{-1}\)
Answer & Solution
Correct Answer
(B) \(10 \mathrm{~m} \mathrm{~s}^{-1}\)
Step-by-step Solution
Detailed explanation
\( \vec{v}_1 = 20 \hat{j} \mathrm{~m} \mathrm{~s}^{-1}, \vec{v}_2 = 10 \hat{i} \mathrm{~m} \mathrm{~s}^{-1} \) \( \vec{V}_{CM} = \frac{m_1 \vec{v}_1 + m_2 \vec{v}_2}{m_1 + m_2} = \frac{2(20 \hat{j}) + 3(10 \hat{i})}{2 + 3} \mathrm{~m} \mathrm{~s}^{-1} \)…
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