AP EAMCET · PHYSICS · Oscillations
Three blocks of masses \(700 \mathrm{~g}, 500 \mathrm{~g}\) and \(400 \mathrm{~g}\) suspended at the end of a spring as shown in the figure, are in equilibrium.
When the \(700 \mathrm{~g}\) block is removed, the system has a period of oscillations of \(3 \mathrm{~s}\). If both \(700 \mathrm{~g}\) and \(500 \mathrm{~g}\) blocks are removed, the period of oscillation becomes
- A \(1 \mathrm{~s}\)
- B \(2 \mathrm{~s}\)
- C \(3 \mathrm{~s}\)
- D \(\sqrt{\frac{12}{5}} \mathrm{~s}\)
Answer & Solution
Correct Answer
(B) \(2 \mathrm{~s}\)
Step-by-step Solution
Detailed explanation
The given situation is shown in the following figure When the block of \(700 \mathrm{~g}\) is removed, then period of oscillation is given as \(\begin{aligned} T^{\prime} & =2 \pi \sqrt{\frac{m}{k}} \\ & =2 \pi \sqrt{\frac{(700+500+400-700) \times 10^{-3}}{k}} \end{aligned}\)…
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