AP EAMCET · PHYSICS · Laws of Motion
A body is travelling with \(10 \mathrm{~ms}^{-1}\) on a rough horizontal surface. It's velocity after \(2 \mathrm{~s}\) is \(4 \mathrm{~ms}^{-1}\). The coefficient of kinetic friction between the block and the plane is
(acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )
- A \(0.4\)
- B \(0.3\)
- C \(0.5\)
- D \(0.2\)
Answer & Solution
Correct Answer
(B) \(0.3\)
Step-by-step Solution
Detailed explanation
Initial speed of body on the horizontal rough surfaces, \(u=10 \mathrm{~ms}^{-1}\) Final velocity, \(v=4 \mathrm{~ms}^{-1}\) and \(t=2 \mathrm{~s}\). If \(a\) be the retardation due to friction, then by using equation, \(v=u-a t\) \(\Rightarrow \quad 4=10-a \times 2\)…
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