AP EAMCET · Maths · Probability
Suppose that a bag \(A\) contains \(n\) red and 2 black balls and another bag \(B\) contains 2 red and \(n\) black balls. One of the two bags is selected at random and two balls are drawn from it at a time. When it is known that the two balls drawn are red, if the probability that those two balls drawn are from bag \(A\) is \(\frac{6}{7}\), then \(n=\)
- A 6
- B 4
- C 8
- D 7
Answer & Solution
Correct Answer
(B) 4
Step-by-step Solution
Detailed explanation
Let \(E_1\) be the event that the ball is drawn from bag \(A. E_2\) be the event that it is drawn from bag \((B)\) and \(E\) that ball is red. Given, \(P\left(\frac{E_1}{E}\right)=\frac{6}{7}\) By Baye's, theorem,…
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