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AP EAMCET · Maths · Probability

Suppose that a bag \(A\) contains \(n\) red and 2 black balls and another bag \(B\) contains 2 red and \(n\) black balls. One of the two bags is selected at random and two balls are drawn from it at a time. When it is known that the two balls drawn are red, if the probability that those two balls drawn are from bag \(A\) is \(\frac{6}{7}\), then \(n=\)

  1. A 6
  2. B 4
  3. C 8
  4. D 7
Verified Solution

Answer & Solution

Correct Answer

(B) 4

Step-by-step Solution

Detailed explanation

Let \(E_1\) be the event that the ball is drawn from bag \(A. E_2\) be the event that it is drawn from bag \((B)\) and \(E\) that ball is red. Given, \(P\left(\frac{E_1}{E}\right)=\frac{6}{7}\) By Baye's, theorem,…