AP EAMCET · PHYSICS · Laws of Motion
A body is sliding down a rough inclined plane. The coefficient of friction between the body and the plane is 0.5 . The ratio of the net force required for the body to slide down and the normal reaction on the body is \(1: 2\). Then the angle of the inclined plane is
- A \(15^{\circ}\)
- B \(30^{\circ}\)
- C \(45^{\circ}\)
- D \(60^{\circ}\)
Answer & Solution
Correct Answer
(C) \(45^{\circ}\)
Step-by-step Solution
Detailed explanation
\[ \mu=0.5, \frac{F}{R}=\frac{1}{2} \] Net force acting downward \(=m g \sin \theta-f\) where, \(f=\) frictional force \(=\mu R(R=\) Normal reaction \()\) \(=\mu m g \cos \theta\) \[ \frac{F}{R}=\frac{1}{2} \]…
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