AP EAMCET · PHYSICS · Mechanical Properties of Fluids
A solid float such that its \((1 / 3)\) rd part is above water surface. Then, the density of solid is
- A \(744 \mathrm{~kg} \mathrm{~m}^{-3}\)
- B \(\frac{1000}{3} \mathrm{~kg} \mathrm{~m}^{-3}\)
- C \(\frac{2000}{3} \mathrm{~kg} \mathrm{~m}^{-3}\)
- D \(910 \mathrm{~kg} \mathrm{~m}^{-3}\)
Answer & Solution
Correct Answer
(C) \(\frac{2000}{3} \mathrm{~kg} \mathrm{~m}^{-3}\)
Step-by-step Solution
Detailed explanation
Given that, \(\left(\frac{1}{3}\right) \operatorname{rd}\) part of body is above the water surface. \(\therefore\) Volume of body outside the water \(=\frac{1}{3}\)(volume of body) \(V_o=\frac{1}{3} V\) \(\therefore\) Volume of body inside,…
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