ExamBro
ExamBro
AP EAMCET · Maths · Three Dimensional Geometry

If the distance between the planes \(2 x+y+z+1=0\) and \(2 x+y+z+\alpha=0\) is 3 units, then product of all possible values of \(\alpha\) is

  1. A \(-43\)
  2. B \(43\)
  3. C \(53\)
  4. D \(-53\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(-53\)

Step-by-step Solution

Detailed explanation

Given two planes are \(2 x+y+z+1=0\) and \(2 x+y+z+\alpha=0\) Since, these are parallel planes So, distance between them…