AP EAMCET · PHYSICS · Ray Optics
The diameter of objective of a telescope is \(1 \mathrm{~m}\) Its resolving limit for the light of wavelength \(4538 Ã…\), will be
- A \(5.54 \times 10^{-7} \mathrm{rad}\)
- B \(2.54 \times 10^{-4} \mathrm{rad}\)
- C \(6.54 \times 10^{-7} \mathrm{rad}\)
- D None of these
Answer & Solution
Correct Answer
(A) \(5.54 \times 10^{-7} \mathrm{rad}\)
Step-by-step Solution
Detailed explanation
Resolving limit \(d \theta=\frac{1.22 \lambda}{a}\) \(=\frac{1.22 \times 4538 \times 10^{-10}}{1}\) \(=5.54 \times 10^{-7} \mathrm{rad}\)
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