AP EAMCET · PHYSICS · Mechanical Properties of Solids
A \(20 \mathrm{~g}\) copper block is suspended by a vertical spring causing \(1 \mathrm{~cm}\) elongation over the natural length of spring. If a beaker of water is placed below the block so that the copper block is completely immersed in the liquid, the elongation of the spring is
(Density of copper \(9000 \mathrm{~kg} \mathrm{~m}^{-3}\), Density of water 1000 \(\mathrm{kg} \mathrm{m}^{-3}, \mathrm{~g}=10 \mathrm{~ms}^{-2}\) )
- A \(0.25 \mathrm{~cm}\)
- B \(0.15 \mathrm{~cm}\)
- C \(0.78 \mathrm{~cm}\)
- D \(0.89 \mathrm{~cm}\)
Answer & Solution
Correct Answer
(D) \(0.89 \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
Mass of Block, \(\mathrm{m}=20 \mathrm{~g}=20 \times 10^{-3} \mathrm{~kg}\) Elongation, \(x=1 \mathrm{~cm}=0.01 \mathrm{~m}\) Spring elongation after immersed in water, \(\mathrm{x}^{\prime}=\) ? Density, \(\rho=9000 \mathrm{~kg} / \mathrm{m}^3\) Density of water,…
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