AP EAMCET · PHYSICS · Laws of Motion
A block of mass \(10 \mathrm{~kg}\) is placed on a horizontal frictionless surface and is attached to a cord which passes over two light frictionless pulleys as shown in the figure. The hanging block tied to the other end of the cord is initially at rest \(2 \mathrm{~m}\) above the horizontal floor.If the hanging block strikes the floor \(2 \mathrm{~s}\) after the system is released, then weight of the hanging block is ....... \(\left(g=10 \mathrm{~ms}^{-2}\right)\)
- A 22.22 N
- B 11.11 N
- C 1.11 N
- D 2.22 N
Answer & Solution
Correct Answer
(B) 11.11 N
Step-by-step Solution
Detailed explanation
For hanging block, \[ \begin{aligned} & \quad s=u t+\frac{1}{2} a t^2[\because u=0] \Rightarrow 2=\frac{1}{2} \times a \times 2^2 \\ & \Rightarrow \quad a=1 \mathrm{~ms}^{-2} \end{aligned} \] So, velocity of hanging block \(=\) velocity of \(10 \mathrm{~kg}\) block after…
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