AP EAMCET · Maths · Parabola
\(y=3 x-2\) is a straight line touching the parabola \((y-3)^2=12(x-2)\). If a line drawn perpendicular to this line at \(P\) on it, touches the given parabola, then the point \(P\) is
- A \((-1,-5)\)
- B \((-1,5)\)
- C \((-2,-8)\)
- D \((2,4)\)
Answer & Solution
Correct Answer
(A) \((-1,-5)\)
Step-by-step Solution
Detailed explanation
According to the given information, Angle between the tangents is \(90^{\circ}\). \(\Rightarrow\) The point on the directrix Here, \(x-2=-3\) \(x=-1\) is directrix Given tangent is \(y=3 x-2\)…
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