AP EAMCET · Chemistry · Chemical Equilibrium
For the following given equilibrium reaction \(\frac{\mathrm{K}_{\mathrm{c}}}{\mathrm{K}_{\mathrm{p}}}\) is equal to 1076 at \(\mathrm{T}(\mathrm{K})\). What is the value of T (in K) ? ( \(\mathrm{R}=0.082 \mathrm{~L}\)-atm \(\mathrm{K}^{-1} \mathrm{~mol}^{-1}\) )
\(\mathrm{N}_2(\mathrm{~g})+3 \mathrm{H}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_3(\mathrm{~g})\)
- A \(500\)
- B \(600\)
- C \(400\)
- D \(450\)
Answer & Solution
Correct Answer
(C) \(400\)
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