ExamBro
ExamBro
AP EAMCET · Chemistry · Chemical Equilibrium

For the following given equilibrium reaction \(\frac{\mathrm{K}_{\mathrm{c}}}{\mathrm{K}_{\mathrm{p}}}\) is equal to 1076 at \(\mathrm{T}(\mathrm{K})\). What is the value of T (in K) ? ( \(\mathrm{R}=0.082 \mathrm{~L}\)-atm \(\mathrm{K}^{-1} \mathrm{~mol}^{-1}\) )
\(\mathrm{N}_2(\mathrm{~g})+3 \mathrm{H}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_3(\mathrm{~g})\)

  1. A \(500\)
  2. B \(600\)
  3. C \(400\)
  4. D \(450\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(400\)

Step-by-step Solution

Detailed explanation

NO SOLUTION