AP EAMCET · Maths · Limits
\(\lim _{x \rightarrow 3} \frac{x^3-27}{x^2-9}=\)
- A \(\frac{3}{2}\)
- B \(\frac{9}{2}\)
- C \(3\)
- D \(2\)
Answer & Solution
Correct Answer
(B) \(\frac{9}{2}\)
Step-by-step Solution
Detailed explanation
\(\lim _{x \rightarrow 3} \frac{x^3-27}{x^2-9} = \lim _{x \rightarrow 3} \frac{(x-3)\left(x^2+9+3 x\right)}{(x-3)(x+3)}=\frac{9}{2}\).
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