AP EAMCET · Maths · Probability
If \(\mathrm{X}\) is a random variable with the following probability distribution
\(\begin{array}{|l|c|c|c|}
\hline \mathrm{X}=x & -3 & 6 & 9 \\
\hline \mathrm{P}(\mathrm{X}=x) & \frac{1}{6} & \frac{1}{2} & \frac{1}{3} \\
\hline
\end{array}\)
then the variance of \(\mathrm{X}\) is
- A \(\frac{65}{4}\)
- B \(\frac{65}{2}\)
- C \(\frac{65}{3}\)
- D 65
Answer & Solution
Correct Answer
(A) \(\frac{65}{4}\)
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