AP EAMCET · Maths · Properties of Triangles
With the usual notations, in a , if and , then
- A
- B
- C
- D
Answer & Solution
Correct Answer
(C)
Step-by-step Solution
Detailed explanation
We have, a=2, b=6 and c=3+1 Using cosine rule, we get, cosC=a2+b2-c22ab =6-2346 =3-122 And cosA=c2+b2-a22cb =4+23+6-423+16=12 Now, sin2C-sin2A=1-cos2C-1-cos2A =cos2A-cos2C =12-3-1222 =12-4-238 =34.
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