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AP EAMCET · Maths · Circle

Which circle among the following bisects the circumference of the circle \(x^2+y^2-8 x-6 y+23=0\) ?

  1. A \(x^2+y^2-6 x-4 y+9=0\)
  2. B \(x^2+y^2+6 x+4 y-9=0\)
  3. C \(x^2+y^2-6 x+4 y-9=0\)
  4. D \(x^2+y^2+6 x-4 y+9=0\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(x^2+y^2-6 x-4 y+9=0\)

Step-by-step Solution

Detailed explanation

Given circle, \[ x^2+y^2-8 x-6 y+23=0 \] Centre of this circle is \((4,3)\). If the equation of radical axis of circle \(S_1\) and \(S_2\) passes through \((4,3)\), then \(S_2\) bisect the circumference of \(S_1\). Option (a) Let \(S_2=x^2+y^2-6 x-4 y+9=0\) Then, equation of…