AP EAMCET · Maths · Circle
When the origin is shifted to \((h, k)\) by translation of axes, the transformed equation of \(x^2+2 x+2 y-7=0\) does not contain \(x\) term and constant term. Then \((2 h+k)=\)
- A \(\frac{7}{2}\)
- B \(\frac{1}{2}\)
- C 2
- D 0
Answer & Solution
Correct Answer
(C) 2
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { } \mathrm{X}+h=x, \mathrm{Y}+k=y \\ & (\mathrm{X}+h)^2+2(\mathrm{X}+h)+2(\mathrm{Y}+k)-7=0 \\ & \mathrm{X}^2+(2 h+2) \mathrm{X}+2 \mathrm{Y}+h^2+2 h+2 k-7=0 \end{aligned}\) To remove X - term, \(2 h+2=0 \Rightarrow h=-1\) To remove constant term,…
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