AP EAMCET · Maths · Permutation Combination
A question paper contains 4 questions each having 4 alternative answers. The number of ways that a candidate can answer one or more questions is
- A 255
- B 256
- C 624
- D 625
Answer & Solution
Correct Answer
(C) 624
Step-by-step Solution
Detailed explanation
Number of outcomes per question = \(4 \text{ (answers)} + 1 \text{ (not answer)} = 5\) Total ways to answer all questions = \(5^4 = 625\) Ways to answer one or more questions = \(5^4 - 1 \text{ (way to answer none)} = 625 - 1 = 624\)
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