AP EAMCET · Maths · Properties of Triangles
What is the greatest angle of the triangle whose sides are \(x^2+x+1,2 x+1, x^2-1\) ?
- A \(A=120^{\circ}\)
- B \(A=90^{\circ}\)
- C \(A=135^{\circ}\)
- D \(A=60^{\circ}\)
Answer & Solution
Correct Answer
(A) \(A=120^{\circ}\)
Step-by-step Solution
Detailed explanation
Sides of triangle are \(\begin{aligned} & x^2+x+1,2 x+1 \text { and } x^2-1 \\ & x^2+x+1 \text { is the greatest side. }\end{aligned}\) \(\therefore \cos A=\frac{b^2+c^2-a^2}{2 b c}\) Here, \(a=x^2+x+1, b=2 x+1, c=x^2-1\)…
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